d^2f=ln(4x^2-5y^3)

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Solution for d^2f=ln(4x^2-5y^3) equation: 


Simplifying
d2f = ln(4x2 + -5y3)
d2f = (4x2 * ln + -5y3 * ln)
d2f = (4lnx2 + -5lny3)

Solving
d2f = 4lnx2 + -5lny3

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by 'f'.
d2 = 4f-1lnx2 + -5f-1lny3

Simplifying
d2 = 4f-1lnx2 + -5f-1lny3

Reorder the terms:
d2 + -4f-1lnx2 + 5f-1lny3 = 4f-1lnx2 + -4f-1lnx2 + -5f-1lny3 + 5f-1lny3

Combine like terms: 4f-1lnx2 + -4f-1lnx2 = 0
d2 + -4f-1lnx2 + 5f-1lny3 = 0 + -5f-1lny3 + 5f-1lny3
d2 + -4f-1lnx2 + 5f-1lny3 = -5f-1lny3 + 5f-1lny3

Combine like terms: -5f-1lny3 + 5f-1lny3 = 0
d2 + -4f-1lnx2 + 5f-1lny3 = 0

The solution to this equation could not be determined.

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